Circle Ellipse Parabola Hyperbola
Circle Ellipse Parabola Hyperbola

GENERAL FORM TO STANDARD FORM OF HYPERBOLA

Input the value of your equation.

  • One coefficient must be positive and the other must be negative: A > 0, B < 0 or A < 0, B > 0

    • Example: 9x²-4y²-54x-16y+23=0


    Here are the steps:

    REMINDER:

    Prepare your pen and a piece of paper for writing your answers.

    Given:

    x 2 - y 2 + x + y + = 0

    STEP 1: Regroup the coefficient x and coefficient y and bring the constant on the right side of the equation and change its sign.

    STEP 2: Bring out the common factor of the coefficient x and coefficient y.

    STEP 3: By using the completing the square, get the perfect square trinomial of coefficient x and coefficient y.

    STEP 4: Along with the constant on the right side of the equation, put also the common factor to make it balance then multiply it to the square (n²)of the perfect square trinomial of the coefficient x and coefficient y.

    STEP 5: Simplify the right side of the equation and make the perfect square trinomial into square of binomial.

    STEP 6: Divide both sides of the equation by the constant on the right side, then simplify.

    Final Answer:

    ( )² - ( )² = 1

    The formula for getting the c value is √c² = √a² + √b².

    • a=
    • b=
    • c=
    • a²=
    • b²=
    • c²=

    Your Answers:

    Center:

    Vertices: (h±a, k) / (h, k±a)

    Foci: (h±c, k) / (h, k±c)

    Asymptote: (y - k) = ±b/a (x - h) or (y - k) = ±a/b (x - h)

    Orientation: